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Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It only takes a minute to up. Connect and share knowledge within a single location that is structured and easy to search. I'm throwing an event where every individual is suppose to meet every other individual so I'm trying figure out how to rotate them. My friends say its easy but they have yet to come up with an answer and our event looms closer and closer.
The first half is easy, you Speed dating seating plan have the odds stay in their seats and rotate evens. Then take the 10 odds, re them, repeat. Then split to At this point, my head hurts and it's taking more time to tell my guests who to meet than they spend meeting them.
Assume whatever table arrangement works, we have a variety. Regardless, i think the long narrow solution below works. Seat your guests at a long banquet table, but don't seat anyone at the he of the table. So like this:. I think the answer is: Make one person stationary, rotate all the folks. This actually works. Each person in the top row "meets" the corresponding person just below in the bottom row. For sixteen people, sort them into four groups of four: A,B,C,D. Rotate the people within A, and those within B, etc, so they meet Speed dating seating plan within their own group. Then, counting neighbours as next-to, opposite, and opposite's next-to, some people can meet all 15 others, but everyone else meets only 11 others.
For twelve people, the chairs 1 to 6 on one side of the table, and 7 to 12 on the other side, so 1 faces 7, 2 faces 8 and so on. Please find the program output below. Every line represents the way how people should be paired in that meeting. The people are ed from 0 to up to this community. The best answers are voted up and rise to the top. Stack Overflow for Teams — Collaborate and share knowledge with a Speed dating seating plan group.
Create a free Team What is Teams? Learn more. How to rotate n individuals at a dinner party so that every guest meets every other guests Ask Question. Asked 10 years, 3 months ago. Active 1 year ago. Viewed 41k times. Improve this question. DanielEli DanielEli 1 1 gold badge 2 2 silver badges 7 7 bronze badges.
Where were these in school? Are guests seated around one large round table? Does "meet" mean being seated next to a person? Are you trying to minimize the overall of "shuffles", or something about the magnitude of the shuffles as Speed dating seating plan e. If they are pretty familiar, you can group them by successively longer prefixes of their in binary. Within each group, the ones whose bit after the prefix is 0 are evens and the others odds. Although, the best way is still to work everything out in advance, write it down on cards and have everyone take a card on arrival.
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Active Oldest Votes. Only you will have 10 on each side. Improve this answer. So this is equivalent to fixing the odds and rotating the evens. By keeping one person fixed see beloweveryone will meet everyone else like speed-networking. Add a comment. Jesse Phillips Jesse Phillips 2 2 bronze badges. Make a box around 1, it is stationary. For each couplet sitting across the linemake a line on the graph connecting them. Round 2, rotate all the s around the line, except 1 it's in a box. You'll see that it just works out. I don't know why. For any group of 2n people, there will be 2n-1 rounds, with everyone meeting everyone else once.
If you have an odd of people, just add an imaginary person to the mix, with the result that each person has one round off from meeting anyone. Speed dating seating plan Phillips suggests seating everyone at a long banquet table and rotating as in a little don's answer, but one person sitting at a corner remains fixed, while the other 2n-1 people rotate cyclically. Very nice solution! Empy2 Empy2 46k 1 1 gold badge 33 33 silver badges 79 79 bronze badges. Jatin Sanghvi Jatin Sanghvi 3 3 bronze badges. up or log in up using Google.
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Speed dating seating plan